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Redox Reactions and Electrochemistry

Calculate the E.M.F of the electrode-concentration cell : $H_2(P_1),HCl,H_2(P_2)$ at $25^{\large\circ}C$ if $P_1$ = 1atm and $P_2$ = 0.25atm.The E.M.F. 'E' is

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(A) 0.016V

(B) 0.018V

(C) 0.017V

(D) 0.18V

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Redox Reactions and Electrochemistry practice questions for JEE

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